6IV Ditto Needed!!!

[ReneeKelly]

Really needing a 6IV ditto (anything but ENG) for breeding!

I have a few pokemon I can offer in exchange!!
> Jirachi
> Darkrai
> Mew
> Most other legends
> A few shiny legends
> A few shiny pokemon

Thank you to whoever can help me!

[Porygon-Z]

All FS (I'll be using that term for Friend Safari) Pokemon have two perfect IVs, so that's 1/1 if you want a 2 IV Ditto.

There is a 1/32 chance you can get any IV from 0 to 31. So if you want a 3 IV Ditto, there is a 1/32 chance.

Same with 4 IVs, you just multiply the chance by 32 since there are 32 new possible IVs, or 1/1024.

You keep going with 5 IVs and 6IVs to get 1/32768 and 1/1048576 respectively.

Comparing this with a regular wild Ditto you can catch in the Pokemon Village, that has a 1/1073741824 (more than 1/one trillion) chance to perfect IVs.

2 IV FS Pokemon: 1/1
3 IV FS Pokemon: 1/32
4 IV FS Pokemon: 1/1024
5 IV FS Pokemon: 1/32768
6 IV FS Pokemon: 1/1048576
0 IV Normal Pokemon: 31/32
1 IV Normal Pokemon: 1/32
2 IV Normal Pokemon: 1/1024
3 IV Normal Pokemon: 1/32768
4 IV Normal Pokemon: 1/1048576
5 IV Normal Pokemon: 1/33554432
6 IV Normal Pokemon: 1/1073741824

Information from.
http://pokemondb.net/pokebase/180723/what-are-chances-finding-ditto-with-perfect-ivs-friend-safari

[Crevab]

True, but that's for legit. There's copies of hacked perfect dittos floating aboot

[Fox Goddess Inari]

Really needing a 6IV ditto (anything but ENG) for breeding!

I have a few pokemon I can offer in exchange!!
> Jirachi
> Darkrai
> Mew
> Most other legends
> A few shiny legends
> A few shiny pokemon

Thank you to whoever can help me!

Hi sweetie, I'm gonna give you a 6iv jap ditto, no payment required so keep your precious pokemons kay. :3

[joefish67]

I have a shiny one if you want that

[Oromb]

Porygon Z dont lie:

The chance for 2IV pkmn in FS is 100%, but:

P(3IV or more in FS)= 1-(31/32)^4 = 11.93% (for Math geeks: =F(4;1/32;4)-F(4;1/32;1) )

P(4IV or more in FS)= 1-[(31/32)^4 + (31/32)^3*(1/32)*4] = 0.5618%

P(5IV or more in FS)= (1/32)^3*(31/32)*4+(1/32)^4 = 0.01192%

P(6IV in FS)= (1/32)^4= 0.00009537% (you had the last one right too)

- - - Updated - - -

But if you youse PokeNav in ORAS your chances rise if you only catch the ones with 3 Stars on them:

P(6IV) for example is equal to (1/32)^3 = 0.00305%

[Porygon-Z]

It wasn't my math, plus it was made before ORAS. I left a link.